### Hints and Guidelines

The problem can be divided by four logical parts:

• Check of all numbers in the given range, and then loop.
• Check the conditions of problem according to every number in the given range.
• Printing the numbers.

First part is ordinary - we read three integer numbers from the console, so we will use int.

We have already came together with thesecond part - initialize the for loop. It is a bit tricky - in the explanation is mentioned that the numbers have to be printed in reversed order. This means that initial value of variable i will be bigger, and from the examples we can see that it is M. So the final value of i should be N. The fact that we will print the results in reversed order and the values of i, suggests that the step would be decreased by 1.

After we have initialized the for loop, it comes the third part of the problem - check in problem description if the given number is divisible both to 2 and 3 without reminder. We will do this with one simple if check , that we will leave to the reader to do it by themselves.

Another tricky part of this problem is that apart of the above check we need to do another one - if number is equal to the "stop" number, entered from the console on the third line. To reach this test,number we check, should pass the above one. For this reason we will build another if construction, that we will nest in the previous one. If the condition is true, we need to stop program from printing, we can do this using operator break, and it will lead us out of the for loop.

If condition of the check whether the number is equal with "stop" number returns result false, our program should continue to print. This covers fourth and last part of our program.