# Problem: Back to the Past

Ivan is **18 years old** and receives an inheritance that consists of **X** money and a **time machine**. He decides **to return to 1800**, but does not know **if the money** will **be enough** to live without working. Write **a program that calculates** if Ivan **will have enough money** to not have to work until a particular year (inclusive). Assuming that **for every even** (1800, 1802, etc.) year he **will spend 12 000 dollars**. For **every odd one** (1801, 1803, etc.) he will spend **12 000 + 50 * [the age he will have reached in the given year]**.

## Input Data

The input is read from the console and **contains exactly 2 lines**:

**Inherited money**– a real number in the range [**1.00 … 1 000 000.00**].**Year, until which he has to live in the past (inclusive)**– integer number in the range [**1801 … 1900**].

## Output Data

**Print** on the console **1 line**. The **sum** must be **formatted** up to the **two symbols after the decimal point**:

- If
**money is enough**:**"Yes! He will live a carefree life and will have {N} dollars left."**– where**N**is the money that will remain.

- If
**money is NOT enough**:**"He will need {М} dollars to survive."**– where**M**is the sum that**is NOT enough**.

## Sample Input and Output

Input |
Output |
Explanations |
---|---|---|

50000 1802 |
Yes! He will live a carefree life and will have 13050.00 dollars left. |
1800 → |

100000.15 1808 |
He will need 12399.85 dollars to survive. |
1800 → |

## Reading the Input Data

The method to solve this task is no different than the previous ones, so we start **declaring and initializing** the necessary variables:

The requirements say that Ivan is 18 years old, so when declaring the variable ** years** we assign it an initial value of

**18**. We read the other variables from the console.

## Iterating through the Years

Using a ** for loop**, we will iterate through all years. We

**start from 1800**– the year in that Ivan returns, and we reach the

**year until which he must live in the past**. We check in the loop if the current year is

**even**or

**odd**. We do this by

**division with remainder**(

**) by 2. If the year is**

`%`

**even**, we subtract from

`heritage`

**12000**, and if is

**odd**, we subtract from

`heritage`

**12000 + 50 * (years)**.

## Checking if Heritage is Enough and Printing the Output

Finally we need to print out the results by checking **if the heritage** is enough to live without working or not. If the

**is a**

`heritage`

**positive number**, we print: “

**”, and if it is a**

`Yes! He will live a carefree life and will have {N} dollars left.`

**negative number**: “

**”. Do not forget to format the sum up to the second symbol after the decimal point.**

`He will need {М} dollars to survive.`

**Hint**: Consider using the ** Math.Abs(…)** function when printing the output, if the heritage is not enough.

## Testing in the Judge System

Test your solution here: https://judge.softuni.org/Contests/Practice/Index/511#2.